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| Tweet Topic Started: Nov 15 2011, 03:01:59 PM (16,053 Views) | |
| Chipster-roo | Nov 8 2015, 02:59:29 PM Post #1156 |
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Growing Tree
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Blackberry 22 Silverweed 7 +1 -1
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| Acacia Heartstrings | Nov 8 2015, 05:18:11 PM Post #1157 |
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Blackberry
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Blackberry 21 Silverweed 8 -1 +1 Never surrender!
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| Fivergoalkeeper | Nov 10 2015, 03:56:36 PM Post #1158 |
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Dandelion
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Blackberry 20 Silverweed 9 -1 +1
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| Chipster-roo | Nov 10 2015, 04:33:45 PM Post #1159 |
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Growing Tree
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Blackberry 21 Silverweed 8 +1 -1 |
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| Acacia Heartstrings | Nov 10 2015, 07:01:45 PM Post #1160 |
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Blackberry
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Blackberry 20 Silverweed 9 -1 +1
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| Foxbrow | Nov 11 2015, 03:53:18 AM Post #1161 |
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Dandelion
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I believe this duel would eventually come to an end, but so far, Blackberry and Silverweed are battling for our favor for over two pages already and their score is exactly the same as it was when they started. I don't know about you, but the Black Rabbit starts to be a bit impatient. So what about bringing another mechanics into the game: The Trial of Ghosts. There were originally 33 characters in the beginning. I suggest that with every round, the Black Rabbit would recieve a counter (representing a ghost of the past character). And once he would hit the number 32, there will be no more ghosts to join the trial, so he would take the one with less points from the game to join his realm, leaving the other to becoma a winner. (I believe that 32 rounds is enough to give a chance to turn the tables same like defending the leading position) What do you think? |
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| Chipster-roo | Nov 11 2015, 11:39:40 AM Post #1162 |
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Growing Tree
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I agree that this is getting way too long. The idea you suggested sounds interesting. How long would each round last? |
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| Myrkin | Nov 11 2015, 12:07:14 PM Post #1163 |
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Fiver
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So... In short, when there are two rabbits left standing, the one with fewest points automatically dies? |
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| Foxbrow | Nov 11 2015, 03:27:53 PM Post #1164 |
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Dandelion
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By round I mean one person posting. So instead of this: rabbit one -1 rabbit two +1 You'll be posting this: rabbit one -1 rabbit two +1 Black Rabbit +1 together with the total count of points.
Not automatically, but after a limited period of time, the weaker one would die (even if the difference is just one point). There can be also a tie on the critical round, in that case the next round would decide. However, since we lost one point somewhere during the play, we now have only 29 points in the game, so there is no chance for a tie anyway. |
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| Acacia Heartstrings | Nov 12 2015, 10:44:38 AM Post #1165 |
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Blackberry
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I do not understand anything XD But this game is since November 2011 Not bad is longer. |
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| Chipster-roo | Nov 12 2015, 01:35:15 PM Post #1166 |
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Growing Tree
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So after 32 more posts, if the game is not over, the one with the most points wins? |
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| Myrkin | Nov 15 2015, 07:37:11 AM Post #1167 |
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Fiver
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Alternatively, we could call it a tie, naming both Blackerry and Silverweed winners, and then start another round with all characters.
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| Acacia Heartstrings | Nov 15 2015, 10:34:45 AM Post #1168 |
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Blackberry
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How about a battle of Rap ?, the winner takes all! ...Which is the prize?
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| Myrkin | Nov 24 2015, 04:27:45 PM Post #1169 |
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Fiver
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Okay. Let's give Foxbrow's idea a try. If by 32nd round we will still have two rabbits, then the one with fewer points will automatically meet the Black Rabbit of Inle.Blackberry 21 Silverweed 8 +1 -1 Round +1 |
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| Chipster-roo | Nov 25 2015, 12:32:37 PM Post #1170 |
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Growing Tree
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Blackberry 22 Silverweed 7 +1 -1 2
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