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| Deceleration's 100 math problems thread!; Absolute torture... | |
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| Tweet Topic Started: Aug 4 2011, 04:22 AM (5,616 Views) | |
| Spar | Oct 16 2011, 02:10 AM Post #121 |
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Wandering Scavenger
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22. Aside from all the various inconsistencies in this question (Abrams tanks take point only when under fire, leading a convoy is typically done by a lighter, less costly, vehicle in the event of coming into a mine field. A smart guerrilla would take refuge in a shack quite a bit more than a few yards from an intended target since the RPG-7 would likely kill him at such a close distance, and would also know better than to try and take down an MBT with such an inaccurate weapon, instead he would aim at a troop carrier to optimize kills and better his chances of escaping, as the MBT would be easier to escape from in comparison to a regiment of soldiers. If the guerrilla wanted to actually disable the Abrams he'd be better off using an IED, rather than rolling the dice with the RPG-7. The guerrilla would also wait until the tank is at a 45 degree angle moving away from him before acting as the RPG-7 might not explode unless it impacts at a sharper angle. I could continue this list, but you get the picture.) I get 11.537 degrees to the east if he's firing as the tank is directly north. |
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| Brayzure | Oct 16 2011, 02:29 AM Post #122 |
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The Analytic Commander
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Darn, I've been outsmarted. |
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| Deceleration | Oct 16 2011, 03:24 AM Post #123 |
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Coreling Conquerer
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I get 11.537 degrees east of north as well! Spar is apparently an expert about this topic, has he served in the military before? How I got the answer: The rocket-propelled grenade is 5 times faster than the tank, so it must travel 5 times farther than the tank in the same amount of time, which it must if it is to hit anything. So I simply find the angle that has the sine of 0.2, the decimal equivalent of the ratio between the tank's distance and the grenade's distance. Also, you got question 21 wrong again, SergeantRick. Do you give up? Question 23 An apartment building is 290 feet from the base of the WTC North Tower. From the top, the angle of depression to the base of the North Tower is 63 degrees, and the angle of elevation to the top is 68 degrees. How tall is the North Tower? Question 24 After the North Tower fell, the tallest remaining section was a part of the outer support structure that was about 70 feet high. What is the angle from the top of the building in question 23 to the top of the remaining section of the North Tower (called the Shroud)? Question 25 A car going 50 kilometers per hour slams into a concrete wall. If the maximum deceleration a human in a seat belt can survive is -300 m/s2, how much of the car must be crushed to save the people? I'm not going to post any more questions until all of the previous ones have been answered. |
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| Brayzure | Oct 16 2011, 08:48 AM Post #124 |
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The Analytic Commander
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Question 23: 1,286.93 ft Question 24: The angle of depression is a smidgen over 60 degrees. Question 25: I have no idea how to even attempt that one. |
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| Deceleration | Oct 19 2011, 07:10 PM Post #125 |
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Coreling Conquerer
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You get question 23, your question 24 is inaccurate (gimme 5 decimal places) and you're too lazy to figure out question 25. |
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| Brayzure | Oct 19 2011, 09:54 PM Post #126 |
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The Analytic Commander
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Very well. I noticed a slight inconsistency in my previous answer anyway. Answer 24: 59.84429 degrees. Answer 25: I have not taken physics before, and I have no idea how to solve it, unless you want me to look it up, which I'm sure you don't want. |
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| Spar | Oct 19 2011, 11:51 PM Post #127 |
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Wandering Scavenger
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I have to mention that question 25 is impossible without further information. How long is the vehicle and where are the passengers located? |
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| Deceleration | Oct 20 2011, 03:15 AM Post #128 |
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Coreling Conquerer
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I know your weaknesses now! *maniacal laughter* ![]() The vehicle's length is not a factor. I asked you to find out how much of the vehicle should be crush ed in the collision in order to safely decelerate the vehicle. Presumably the passengers will not be inside this crushable section. |
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| Deceleration | Oct 20 2011, 03:21 AM Post #129 |
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Coreling Conquerer
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Questions 18, 19, 21, and 25 remain unanswered. I will not post any more questions until they have all been answered correctly. |
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| Spar | Oct 20 2011, 03:01 PM Post #130 |
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Wandering Scavenger
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The size, shape and materials of the car are still relevant in negating the effects of a crash. For example in Europe a lot of small cars have a pocket (it's only an inch or so thick) of liquid that acts as a cushion to negate about 15-20 mph of the crash. Other vehicles have an "aerodynamic buffer" that forces the air in front of the vehicle to act as a cushion. Then you have steel body cars, like Lincoln's '71 Continental, which are more likely to put a hole in the concrete wall and keep going. The "crush zone" of modern vehicles isn't a distinct function, even in normal cars, since certain parts will crush at different rates, thanks to the non-uniform shape that modern cars possess. There's a reason that crash tests are done on every car rather than applying a function to them. The formula to figure out each car's optimum crush zone would be almost a full page of functions and it would still be inaccurate. |
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