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| Riddle Answering; Someone asks a riddle, the one who answeres correctly has to ask the next. | |
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| Tweet Topic Started: Aug 20 2010, 11:31 AM (12,848 Views) | |
| kycse | Oct 2 2010, 01:49 PM Post #151 |
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Okay.... (Just for reference, which of my 2 answers was the right answer? The stupid one or the food related one?) Learned some nice riddle, but since I doubt anyone would be able to answer this, I'll just give you the wikipedia summary: http://en.wikipedia.org/wiki/Hilbert%27s_paradox_of_the_Grand_Hotel Read it if you are interested (in math). Lets go with this one, however I'll make this a bit more difficult then the original: Three men were to be executed, however they were given one chance to survive: The three men stay in a line, Man C sees the other two men, man B sees man A and man A sees no one. Everyone gets a white or black hat. When one of the three men answers correctly which hat they wear, all will be amnestied. If one answers wrong, all three will be executed. All they know is: There are 2 black hats and 3 white hats. Furthermore, those three men are friends and quite smart. So they know what (or rather how) the others think. They always have a short time limit (the original riddle says an hour, but I think 2 minutes or less would be sufficient) Of course, being wise as they are they answered right. But the audience was stunned and wondered how that could be possible! So they tested it again and again with every possible combination of the hats and every time one of the three men answered right. How can that be? So your task: Explain for every combination how they answer (for certain, there is always one person who'll definitely know his hat due to deduction). You have to say who answers and why he answers his hat color for certain! I'll write all possible combinations for you: (Monospace for better visualization) Men: A<B<C Combinations: W<W<W W<W<B W<B<W W<B<B B<W<W B<W<B B<B<W Just in case someone wonders: B<B<B is impossible, reread the riddle. Advice: You actually don't have to answer for all 7 combination, there are some combinations that can be explained the same way. |
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| amginE | Oct 3 2010, 12:39 AM Post #152 |
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Let's go in reverse order. B<B<W = Man C answers immediately, since he sees two black hats so he must be a white hat. B<W<B = Man C sees one of each and doesn't say anything for two minutes. Man B knows that Man C did not see two black hats (or else he would have answered). So Man B answers after two minutes are up, since he knows that Man C must have seen one of each (since he sees that Man A is black hat) so he, Man B, must be white hat. B<W<W = Same as previous W<B<B = Man C sees one of each and doesn't answer for two minutes. Man B knows that Man C must have seen either two white hats or one of each. Man B unfortunately doesn't know either, so he doesn't answer for two more minutes. Man A knows that he must be a white hat because if he were a black hat, then B or C would have answered by now. So Man A answers. All other scenarios = Same as previous. Man A answers. |
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| kycse | Oct 3 2010, 05:09 AM Post #153 |
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Somehow it seems we always answer our riddles amgine, do you study math, informatics or something else science related? (Since your riddles tend to be logic riddles, similar to the riddles I know / think of) Anyways, your turn. |
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| amginE | Oct 3 2010, 03:58 PM Post #154 |
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hmm. i graduated college with a bioengineering degree, which isn't particularly related to logic, but i just like logic puzzles, heh. how about you? anyway, here's the riddle. I ask you to pick five cards from a standard 52-card deck. My partner reads out four of the cards in the standard way (e.g. "King of Spades", "7 of Diamonds", so no tricky word play involved or hidden signals) and from that alone, I am able to tell what is the fifth card. (I don't look at the remaining cards in the deck, either). How is this done? |
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| kycse | Oct 4 2010, 03:26 AM Post #155 |
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Well, it's still in the science department... I'll start my bachelor of science in informatics at the RWTH-Aachen next week. As for that riddle... I was never able to figure something like that out, but I'd like to ask for some elaborations first. 1. If you say standard 52-card deck, is it shuffled? Usually they aren't when you've just bought them. (I think they are like that: Ace of X, King of X, Queen of X... Two of X, Ace of Y and so on) 2. If it is shuffled, who shuffled it or does the one who draw the cards, draw them in order from the deck or randomly. (Hmm shuffled deck and random drawing... I wouldn't need to shuffle or to draw randomly then >.>) Deduction 1: If it's not shuffled, and he draws them in order from the top, the 5 cards would be Ace, King, Queen, Jack and Ten of X. If you partner reads the 4 cards, you just have to call the one that's missing. 3. Are the cards read randomly or in a specific order, which might be again be hints, but if no such tricks are involved... Anyways, I'm fairly certain that you can't tell me the fifth card for certain just from the percentages. if your partner would call all the, let's say, 7 of every suit, no suit and no other rank, except the 7, would be more likely. In that case you could just guess. So I'm waiting for your answers first. |
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| amginE | Oct 4 2010, 10:41 AM Post #156 |
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yes, it's shuffled. the audience member who picks the 5 cards can pick any five cards. the assistant plays an important role. the assistant chooses which of the five cards to read and the order in which they are read. |
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| offliner | Oct 10 2010, 01:35 PM Post #157 |
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OK, a standard 52-card deck consists of four colours รก 13 values:
the cards' values are (low to high): Ass(1),2,3,4,5,6,7,8,9,10,Jack(11),Queen(12),King(13) that means:
You will have to use one of them to indicate the colour of the fifth Card, which will have to be the other e.g.: [c12] [h8] [s9] [d9] [h3] 1st card : [h8] or [h3] . . . 5th card : [h3] or [h8] doing so will reduce the number of Cards that can be the fifth from 48 to 12 max(13 - the 1st) The real problem now is to identify the 5th card correctly and unambiguously just through the order of 3 of the remaining 50 cards. I can only think of a way to Identify 6 of the required 12 cards, if the only hint to the final card is the order of these cards. That is: the remaining cards are sorted by Numeric value to:
if we use the example from above the remaining 3 cards would be: [c12] , [s9] and [d9] [c12] is the highest numeric value and will therfor be labeled (L) in the following explanations the values of [s9] and [d9] are equal so we will help us with an aditional rule: Clubs < Diamonds < Hearts < Spades (the actual rule isn't important as long as magican and assistant use the same one) since Diamonds < Spades the result is: L : Queen of Clubs[c12], M : 9 of Spades [s9], S : 9 of Diamonds [d9] Possible combinations are : SML SLM MSL MLS LSM LMS I hope this was somehow more helpfull than irritating
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| guilover | Oct 10 2010, 02:57 PM Post #158 |
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not another one... can't we just do the puzzles that consist of figuring out who owns what breed of dog and what color their houses are? |
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| amginE | Oct 10 2010, 11:40 PM Post #159 |
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lol. i'm giving offliner the credit for this one. he was really close to getting it. basically, the problem is, order gives only 6 possibilities, but there's 12(?) possible cards to differentiate by. now, picture the numbers from 1 to King as a clock that goes from 1 to 13 (Jack - 11 Queen - 12, King - 13) ![]() Now, remember how we have six possible messages by using the order of the cards? Well. imagine that you're only allowed to go clockwise on the clock. And you start at the card of the same suit mentioned earlier. One (small-medium-large) means go clockwise one number. Two (small-large-medium) means go clockwise two numbers. And so on. So, let's say you get the following 5 cards. 5 of spades 2 of diamonds 3 of hearts 4 of clubs J of spades You speak out 5 of spades (which indicates the suit and where on the clock to start at). Then you say, 4 of clubs, 3 of hearts, 2 of diamonds (large-medium-small) which means to move 6 spaces on the circle, moving to the jack of spades. You're probably asking, but wait Amgine. What if I got the Q of spades as the first card? I can only go from 1-6, so it'll never reach! Well, in that case, just call out the Q of spades first, then call the 4 of clubs, 3 of hearts, 2 of diamonds, meaning to move 6 spaces, and you'll end up on the five of spades. This approach basically makes it possible to pinpoint out of seemingly 12 possible cards the one you want using only the order of three cards. Hope the explanation is good enough. If not, I'll try to clarify. Offliner, your turn to come up with an riddle. Edited by amginE, Oct 11 2010, 12:02 AM.
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| amginE | Oct 20 2010, 03:45 PM Post #160 |
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looks like offliner hasn't checked back on the forums since, so I'll make one up to continue this thread. It requires NO MATH so I don't want any complaints. =P You are the leader of the rebellion against the empire. Your battles are fought in space, with thousands of fighter ships fighting from both sides. The problem is, the enemy's fighter ships are really agile and have very strong weapons, so your losses are always very heavy. In the last battle, you sent 1000 fighter ships but only 92 of them came back, and they were all pretty damaged. You notice that the ships that came back all have similar damage patterns. The wings are virtually undamaged, the back and sides of the ships suffered moderate damage, while the front of the ships suffered the most damage. Based on this observation, you tell your engineers to reinforce which part of the ships, and why? (You can only choose to reinforce one part due to exorbant costs and the fact that more armor makes your ships slower) |
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| kycse | Oct 21 2010, 04:22 PM Post #161 |
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From Math to Sci-Fi? Isn't Sci-Fi actually still within the "science"-section of possible questions? Anyways, you got a strange one this time. How are the ships build? Something like a design would be nice, although I don't think the design matters that much... Random guess: The body, especially the parts that connect the wings and the body. If two fleets fight against each other, they have to fight each other from the front, since they meet each other that way first. That's why the front is most heavily damaged. Then, when passing the ships, they aim for the connection points between the body and the wings, to "cut off" the wings, rendering their enemies immobile. |
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| amginE | Oct 21 2010, 04:26 PM Post #162 |
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just using sci-fi as a backdrop to make the story interesting. there's no need to know any science or engineering to solve this. hmm. design doesnt matter. don't even think about how the ship is built or how the parts link up. in fact, you should probably just think of the various parts as A, B, C. A = most damage B = moderate damage C = least damage Which of the three should be reinforced? and you can assume that any part of the ship is just as likely to get hit as any other part. |
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| kycse | Nov 12 2010, 04:48 PM Post #163 |
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Ok, I'm going for the obvious answer: Part A, because it's the most damaged part. |
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| amginE | Nov 12 2010, 07:15 PM Post #164 |
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fail. oh well, it's been so long, so I'll post the answer and the rationale. It should be the LEAST damaged part. Instead of considering the planes that returned, you should be thinking about the planes that did not return. There's two possibilities: 1) They got hit in the most damaged part even more than the planes that came back, and blew up. 2) The weak spot is actually the part that seemed to suffer almost no damage of the planes that returned. The planes that got hit there all blew up. The ones that returned are the lucky ones which did not get hit in the weak spot at all. Since we are assuming that every part of the plane is equally likely to get hit, #2 seems to be the likelier explanation. Apparently, this was a problem that an engineer faced during World War II. He saw the planes that returned, and noticed the damage patterns. He suggested that the least damaged part be reinforced and his hypothesis above was proven to be correct. Someone else go. I want to do some solving for once. |
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| guilover | Nov 14 2010, 10:06 PM Post #165 |
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a man goes to turkey with three women. they don't know eachother beforehand, but each of the pesters him and nags him about everything. they have a marvelous time. what is his occupation? (i made this up. tell me if it's unsolvable, ok?) |
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| amginE | Nov 15 2010, 02:26 AM Post #166 |
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tour guide / translator? |
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| kycse | Nov 15 2010, 02:40 PM Post #167 |
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A man with three wives? (I definitely read to much Wheel of Time with that whole polygamy Aiel stuff) |
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| amginE | Nov 15 2010, 03:01 PM Post #168 |
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ky... why would the man and his three wives not know each other beforehand? or is this your attempt at a joke? |
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| kycse | Nov 15 2010, 03:18 PM Post #169 |
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No, it's just a bad habit... Damn. I disregarded parts of a question again. Edited by kycse, Nov 15 2010, 03:19 PM.
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| guilover | Nov 16 2010, 09:36 PM Post #170 |
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no, he's not a tour-guide. and he did actually say they acted like wives... all the nagging and such. keep guessing... want a hint? |
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| amginE | Nov 17 2010, 01:55 PM Post #171 |
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ok i'll bite. does the fact that it's "turkey" matter? e.g. if i switch "turkey" with "greece" would it affect the answer? Edited by amginE, Nov 17 2010, 01:56 PM.
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| kycse | Nov 17 2010, 03:04 PM Post #172 |
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Another question: Who had a great time? The man AND the women or just the women? |
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| Tetsuki | Nov 19 2010, 05:32 PM Post #173 |
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I would say either a butler or a driver for the car. |
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| amginE | Nov 19 2010, 05:39 PM Post #174 |
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but why would they take the driver along? can't they just get a native (who knows the local landscape) to do the driving? butler...sounds possible. |
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| kycse | Nov 19 2010, 05:50 PM Post #175 |
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No, I don't think he's a butler. "They don't know each other beforehand." I doubt someone would hire a butler just for bringing them around turkey. |
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| Tetsuki | Nov 19 2010, 05:54 PM Post #176 |
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@amginE: rich people tend to take the same driver. burt you are right ky it doesn't really add up. |
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| apoptoxin4869 | Nov 20 2010, 09:20 PM Post #177 |
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Ruler of the flying squirrels
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so which is the question now? |
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| Tetsuki | Nov 21 2010, 07:47 AM Post #178 |
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^ this |
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| apoptoxin4869 | Nov 27 2010, 01:30 AM Post #179 |
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Ruler of the flying squirrels
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psychologist! |
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| guilover | Dec 14 2010, 10:36 PM Post #180 |
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actually, it's a teacher. my teacher to be exact. it happens every year, a trip to turkey to see the art and culture and to tell us it's not really a scary place. i just suck at making up solvable riddles. and checking these threads. but they all had fun, and my APUSH teacher got mistaken for an art teacher, so all's well that ends well. and the 3 ladies got to go shopping. anyway, apop gets it cuz it's kind of psychological. GO APOP! |
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| NG-KK | Jan 7 2011, 02:40 AM Post #181 |
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The emo, again.
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Alright MY turn. Okay, Why did the farmer stand out in his field? I've asked this riddle many times, it is currently unsolvable. Go ahead and have a crack at it.
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| kycse | Jan 8 2011, 04:13 AM Post #182 |
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To be eyecandy for people who drive by and want to photograph the field. To protect his field from crows. |
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| amginE | Jan 8 2011, 04:22 AM Post #183 |
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maybe he was wearing bright red clothes? oh wait, you probably meant "stand-up-outside", not "stand-out" as in looking conspicuous. |
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| Requiem Blade | Jan 8 2011, 06:32 AM Post #184 |
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Isn't it apop's turn to ask a riddle? |
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| apoptoxin4869 | Jan 8 2011, 11:21 AM Post #185 |
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Ruler of the flying squirrels
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i doesnt matter uhhh cuz he wanted a farmers tan
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| amginE | Jan 8 2011, 03:15 PM Post #186 |
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I think there's an unwritten rule that if you don't reply after a week or so when it's your turn then it becomes a free for all. |
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| Requiem Blade | Jan 8 2011, 05:45 PM Post #187 |
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I see. |
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| NG-KK | Jan 8 2011, 11:11 PM Post #188 |
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The emo, again.
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And btw, nope, no right answers yet. And may I say the answer is LAME... =.= Want me to reveal? I'll reveal after 4 yes.es. |
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| apoptoxin4869 | Jan 9 2011, 02:48 PM Post #189 |
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Ruler of the flying squirrels
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it wasnt a farmer it was a scarecrow |
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| guilover | Jan 9 2011, 10:47 PM Post #190 |
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because his wife kicked him out of his house. to get to the other side. 42 |
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| apoptoxin4869 | Jan 9 2011, 10:59 PM Post #191 |
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Ruler of the flying squirrels
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JESUS!!!!! |
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| guilover | Jan 9 2011, 11:06 PM Post #192 |
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well, just so this doesn't turn out like my "riddle", i'm gonna say YES. |
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| apoptoxin4869 | Jan 9 2011, 11:06 PM Post #193 |
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Ruler of the flying squirrels
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XDD I know right??? isnt that the answer to everything??? i did that for something on my test and i got the asnwer right XDDD |
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| amginE | Jan 11 2011, 08:13 PM Post #194 |
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i still think it's probably a word play on "stand out" meaning to "stand-outside" vs "looking conspicuous". it's probably impossible to guess the exact answer. it could be something as corny as 'he stood outside in his field because he wanted to be like Einstein, who was a "standout in his field"'. |
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| KitsuneWannaBe | Jan 14 2011, 11:39 AM Post #195 |
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......So....What's the current question? because that last guess sounded really good. |
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| NG-KK | Jan 16 2011, 03:45 PM Post #196 |
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The emo, again.
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I'm so sorry I disappeared or so long, I had stuff on... Okaay, well I guess no one got the answer. And as always, my riddle remains unanswerable... Why did the farmer stand out in his field? I'm sorry y'all are gonna kill me or this or something... He did it to win the nobel prize... Cause the nobel prize is given to those OUTSTANDING in their fields! O.o HAHAHAHAHAHAH! |
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| apoptoxin4869 | Jan 17 2011, 03:01 PM Post #197 |
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Ruler of the flying squirrels
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LOLOLOLOLOLOL i luff puns |
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| kycse | Jan 19 2011, 01:25 PM Post #198 |
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ok, I want to kill you right now for that xD but still nice pun. |
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| apoptoxin4869 | Jan 19 2011, 10:31 PM Post #199 |
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Ruler of the flying squirrels
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put a another riddle up!!!!!! |
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| Tetsuki | Feb 12 2011, 07:51 AM Post #200 |
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A Naughty Trio I give you a group of three. One is sitting down, and will never get up. The second eats as much as is given to him, yet is always hungry. The third goes away and never returns. |
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uhhh cuz he wanted a farmers tan
8:34 PM Jul 10